Word | Frequency | Number of right neighbors | Number of left neighbors | Ratio |
---|---|---|---|---|
एकै | 187 | 18 | 1 | 18.0000 |
एकीकृत | 156 | 14 | 1 | 14.0000 |
Type | 104 | 13 | 1 | 13.0000 |
हिजो | 162 | 13 | 1 | 13.0000 |
यसो | 123 | 11 | 1 | 11.0000 |
नियमित | 271 | 10 | 1 | 10.0000 |
यसरी | 508 | 10 | 1 | 10.0000 |
त्यसै | 180 | 10 | 1 | 10.0000 |
त्यसैले | 631 | 29 | 3 | 9.6667 |
यसै | 279 | 19 | 2 | 9.5000 |
नागरिकताको | 74 | 9 | 1 | 9.0000 |
उड्डयन | 67 | 9 | 1 | 9.0000 |
नारायणी | 120 | 9 | 1 | 9.0000 |
विसं | 98 | 9 | 1 | 9.0000 |
करिव | 82 | 9 | 1 | 9.0000 |
दश | 119 | 9 | 1 | 9.0000 |
खाना | 162 | 9 | 1 | 9.0000 |
लघुवित्त | 86 | 9 | 1 | 9.0000 |
झन्डै | 95 | 8 | 1 | 8.0000 |
नदी | 98 | 8 | 1 | 8.0000 |
Word | Frequency | Number of right neighbors | Number of left neighbors | Ratio |
---|---|---|---|---|
। | 83186 | 4 | 1062 | 0.0038 |
बताए | 1360 | 1 | 101 | 0.0099 |
बताउनुभयो | 1168 | 1 | 90 | 0.0111 |
जि | 688 | 1 | 68 | 0.0147 |
रू | 719 | 1 | 48 | 0.0208 |
बताउँछन् | 271 | 1 | 23 | 0.0435 |
गर्नुभयो | 592 | 2 | 37 | 0.0541 |
देखिन्छ | 1079 | 3 | 51 | 0.0588 |
थियो | 5169 | 9 | 151 | 0.0596 |
छ | 23445 | 29 | 483 | 0.0600 |
वर्षीय | 256 | 2 | 32 | 0.0625 |
थिए | 2360 | 6 | 95 | 0.0632 |
जनाएको | 1008 | 4 | 61 | 0.0656 |
छिन् | 233 | 1 | 14 | 0.0714 |
थिइन् | 194 | 1 | 13 | 0.0769 |
छन् | 6890 | 15 | 190 | 0.0789 |
महिनादेखि | 73 | 1 | 11 | 0.0909 |
वर्षपछि | 92 | 1 | 11 | 0.0909 |
हुनेछ | 674 | 5 | 53 | 0.0943 |
गई | 132 | 1 | 10 | 0.1000 |
In this subsection, we compute the ratio of the number of right neighbors and the number of left neighbors. Again, we look for words with extreme ratios:
Data for first table:
select word,w.freq,aa.cnt, bb.cnt,aa.cnt/bb.cnt as r from words w, (select w1_id,count(c.w2_id) as cnt from co_n c where w1_id>100 group by w1_id) aa, (select w2_id,count(c.w1_id) as cnt from co_n c where w2_id>100 group by w2_id) bb where w_id=aa.w1_id and aa.w1_id=bb.w2_id order by r desc limit 20;
Diagram data:
select aa.cnt, bb.cnt from (select w1_id,count(c.w2_id) as cnt from co_n c where w1_id>100 group by w1_id) aa, (select w2_id,count(c.w1_id) as cnt from co_n c where w2_id>100 group by w2_id) bb where aa.w1_id=bb.w2_id;
5.1.7.1 Number of NN co-occurrences vs. Frequency I
5.1.7.2 Number of NN co-occurrences vs. Frequency II